0. We have Z 2 0 f= Z 1 0 f+ Z 2 1 f: Howie works out R 1 0 f= 1 2. Question: Prove That Every Continuous Function On A Closed Interval Is Riemann Integrable. Prove that p(x) is Riemann integrable on [0;2] and determine Z 2 0 p(x)dx: Solution: fis continuous so integrable on [0;2]. Proof. ). F ( x) = ∫ a x f ( t) d t. Then F is continuous. That’s a lot of functions. ; Suppose f is Riemann integrable over an interval [-a, a] and { P n} is a sequence of partitions whose mesh converges to zero. Then f2 = 1 everywhere and so is integrable, but fis discontinuous everywhere and hence is non-integrable. R is Riemann integrable i it is bounded and the set S(f) = fx 2 [a;b] j f is not continuous at xg has measure zero. 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